Problem
Problem URL : 톱니바퀴
[1] Answer Code (18. 04. 14)
#include<iostream>
#include<cstring>
using namespace std;
int idx,dir;
int visit[5];
int a[5][9];
int b[5][9];
void solve(int idx, int dir){
if( idx > 4 || idx < 1 || visit[idx]==1) return ;
else {
visit[idx] = 1;
if( dir == 1 ){
for(int i=1; i<=8; i++) b[idx][ i % 8 + 1] = a[idx][i];
}
else {
for(int i=2; i<=8; i++) b[idx][ i-1 ] = a[idx][i];
b[idx][8] = a[idx][1];
}
//Right
if( idx+1 <= 4){
if( a[idx][3] == a[idx+1][7] ){
for(int i=idx+1; i<=4; i++) for(int j=1; j<=9; j++) b[i][j] = a[i][j];
}
else {
solve(idx+1, dir * -1);
}
}
//Left
if( idx-1 >= 1){
if( a[idx][7] == a[idx-1][3]){
for(int i=idx-1; i>0; i--) for(int j=1; j<=9; j++) b[i][j] = a[i][j];
}
else {
solve(idx-1, dir * -1);
}
}
visit[idx] = 0;
} // End of else
}
int main(){
for(int i=1; i<=4; i++)
for(int j=1; j<=8; j++)
scanf("%1d",&a[i][j]);
int tc;
cin >> tc;
for(int i=1; i<=tc; i++){
cin >> idx >> dir;
solve(idx, dir);
for(int i=1; i<=4; i++) for(int j=1; j<=8; j++) a[i][j] = b[i][j];
}
int cnt=0;
if(b[1][1] == 1) cnt += 1;
if(b[2][1] == 1) cnt += 2;
if(b[3][1] == 1) cnt += 4;
if(b[4][1] == 1) cnt += 8;
cout << cnt << endl;
return 0;
}
[2] Answer Code (18. 04. 14)
#include<iostream>
using namespace std;
int idx,dir;
int visit[5];
int a[5][9];
void solve(int idx, int dir){
visit[idx] = 1;
//Right
if( idx+1 <= 4 && a[idx][3] != a[idx+1][7] && !visit[idx+1]){
solve(idx+1, dir * -1);
}
//Left
if( idx-1 >= 1 && a[idx][7] != a[idx-1][3] && !visit[idx-1] ){
solve(idx-1, dir * -1);
}
visit[idx] = 0;
int tmp;
if( dir == 1 ){
tmp = a[idx][8];
for(int i=7; i>0; i--)
a[idx][i+1] = a[idx][i];
a[idx][1] = tmp;
}
else {
tmp = a[idx][1];
for(int i=1; i<=7; i++)
a[idx][i] = a[idx][i+1];
a[idx][8] = tmp;
}
}
int main(){
for(int i=1; i<=4; i++)
for(int j=1; j<=8; j++)
scanf("%1d",&a[i][j]);
int tc;
cin >> tc;
for(int i=1; i<=tc; i++){
cin >> idx >> dir;
solve(idx, dir);
}
int cnt=0;
if(a[1][1] == 1) cnt += 1;
if(a[2][1] == 1) cnt += 2;
if(a[3][1] == 1) cnt += 4;
if(a[4][1] == 1) cnt += 8;
cout << cnt << endl;
return 0;
}
Code Review
[1],[2] Answer Code (18. 04. 14)
-
[1]코드를 이 코드를 보고 [2]으로 Refactoring
-
굉장히 재밌는 문제이다.